5/6y+2/3y=1+1/2y. ?
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Step-by-step explanation:
5/6y + 2/3y = 1 + 1/2y
⇒ ( 5 + 4y )/ 6y = ( 2y + 1 ) / 2y
⇒6y ( 2y + 1 ) = 2y ( 5 + 4y ) ( ∵ By cross multiplication )
⇒ 12y² + 6y = 10y + 8y²
⇒ 12y² - 8y² = 10y - 6y ( ∵ transposing )
⇒ 4y² = 4y
⇒ 4y² - 4y = 0 ( ∵ transposing )
⇒ 4y (y - 1 ) = 0 ( ∵ common )
⇒ y - 1 = (0 / 4y ) ( ∵ transposing )
⇒ y - 1 = 0
⇒ y = 1 is the answer. ( ∵ transposing )
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