5.7 Prove that the length of the tangent drawn from
external point to a circle are equal.
Answers
Answered by
0
Answer:
The attached figure shows two tangents, SK and SR drawn to circle with center O from an external point K.
To prove that: SK=RK
Proof:
Normal and tangent at a point on the circle are perpendicular to each other.
∠OSK=∠ORK=90
o
Using Pythagoras Theorem,
OK
2
=OS
2
+SK
2
............(i)
OK
2
=OR
2
+RK
2
............(ii)
Subtracting (ii) from (i),
OK
2
−OK
2
=OS
2
+SK
2
−OR
2
−RK
2
⟹SK
2
=RK
2
∵OS=OR
SK=RK
Hence, proved
hope it's correct and help full
Attachments:
Similar questions