A partical performs linear S.H.M. of amplitude 4cm. The distance from its mean position at which its K.E. is tree times the P.E. is
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Answer:
P.E. = K.E.
∴12Kx2=12K(A2−x2)=12KA2−12Kx2
∴2x2=A2∴x=A2–√=A1.414=0.71A
Explanation: pls make me branilist..............
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