Question

5.74 of g occupies 1.2 cm3 . Express its density by keeping the significant figure in view

Answer 1

Answer:

$d = \frac{m}{v} \\ d = \frac{5.74}{1.2} \\ \\ 4 \frac{47}{60} \frac{g}{ {cm}^{3} } \\ \\ or \: 4.78 \: \frac{g}{ {cm}^{3} }$

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Answer 2

There are 3 significant figures in the measured mass whereas there are only 2 magnificent significant figures in the measured volume, Hence the density should be expressed to only 2 significant figures.

Density = $\frac{5.74}{1.2} g \: {cm}^{ - 3}$

= 4.8 g ${cm}^{ - 3}$

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