Math, asked by shaheenasalih, 7 months ago

5+8+11+............. +302?

Answers

Answered by yashaswini3679

7

Answer:

15350

Step-by-step explanation:

Given,

Series : 5 + 8 + 11 + ...... + 302

The given series is in AP.

The common difference,

8 - 5 = 3

11 - 8 = 3

So, common difference, d = 3

first term, a = 5

last term, l = 302

an = a + (n - 1) d

302 = 5 + (n - 1)3

297 ÷ 3 = n - 1

99 + 1 = n

n = 100

Sum of n terms of an AP, Sn = n/2[a + l]

= 100/2 [ 5 + 302]

50 × 307

15350

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Answered by Sankalp050

1

Step-by-step explanation:

${ {3}^{2} }^{3} \times {(2 \times {3}^{5}) }^{ - 2} \times {18}^{2 } \\ \\ = {3}^{6} \times \frac{1}{4 \times {3}^{10} } \times {18}^{2} \\ \\ = \frac{ {18}^{2} }{4 \times {3}^{4} } \\ \\ = \frac{ \cancel{18 } \: ^{ \cancel{6}} \: ^{ \cancel{2}}\times { \cancel{18}} \: ^{ \cancel{6 }} \: ^{ \cancel{2}} \: ^1 }{ { \cancel{4 }\:_1}\times { \cancel{3} \: _1} \times { \cancel{3 } \: _1}\times { \cancel{3} \:_1} \times { \cancel{3} \: _1} } \\ \\ = { \huge{ \red{ \boxed{1}}}}$

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