5/8 part of container is filled with water. When 10liters of water is emptied from it, it becomes half full of water . Find the capacity of the container.
deepti33:
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Let the total capacity of the tank be x
5/8 of it is filled => 5/8x
when 10 liters is emptied it reaches half of its capacity
5/8x - 10 = 1/2x
moving 1/2 x to LHS and 10 to RHS
5/8x-1/2x = 10
x(5/8-1/2) = 10
x((5-4)/8)=10
x(1/8) = 10
send 1/8 to RHS
x = 80
5/8 of it is filled => 5/8x
when 10 liters is emptied it reaches half of its capacity
5/8x - 10 = 1/2x
moving 1/2 x to LHS and 10 to RHS
5/8x-1/2x = 10
x(5/8-1/2) = 10
x((5-4)/8)=10
x(1/8) = 10
send 1/8 to RHS
x = 80
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