Question

5.
A 2 kg ball rolls around the edge of a circle with a radius of lm. If it is rolling at a speed of 3 m/s,
what is the centripetal acceleration?
(1) 1 m/s
(2) 3 m/s
(3) 6 m/s
(4) 9 m/s2
6.
Edate​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer: Given:- Mass: 2Kg

Speed: 3m/s

Radius: 1 m

★We have to find centripetal acceleration.

★The centripetal acceleration formula is v²/r

Step-by-step explanation:Let V = 3m/s

r= 1m

Then , Centripetal acceleration = v²/r

=3²/1

=9/1

=9m/s²

Thus, the Centripetal acceleration is 9m/s².

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