Question

5. A bulb is marked 220 V and 40 W. Calculate the current flowing through the bulb

and its resistance.​

Answer 1

Answer:

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Explanation:

The current flowing through the bulb and its resistance is 0.18 A and 1210 ohms respectively. So, the current flowing through the bulb and its resistance is 0.18 A and 1210 ohms respectively

Answer 2

Given:

• Potential difference of bulb = V = 220 V
• Power of the bulb = W = 40 W

To find:

• Resistance of bulb = ?

Solution:

Power can be expressed as voltage times current.

So, we have

☞ P = V I

Substitute the given values

→ 40 = 220 × I

→ I = 40 ÷ 220

→ I = 0.18 A

For finding Resistance, apply Ohm's law.

☞ R = V ÷ I

⇢ R = 220 ÷ 0.18

⇢ R = 1222.22 Ω

∴ Resistance of the bulb = 1222.22 Ω

KNOW MORE:

Some more important formulae of electricity:

• I = Q ÷ t
• Q = n × e
• H = I²Rt
• Number of units = Power consumed × Time
• Resistance in series = R1 + R2 + R3