Question

5. A can do a piece of work in 40 days. He works at it for 8 days and then B finishes the remaining work. How long
will A require to finish the work
remaining work in 16 days. How long will they take to complete the work if they do
it together?​

Answer 1

Now this time, let's assume the work is of eating chocolates.

Assume the total number of chocolates be 80 (L.C.M of 40, 8, 16)

Condition 1: X eats 80 chocolates in 40 days.

Hence efficiency of X is : 2 chocos / day

Condition 2: X work for 8 days. Then Y work for 16 days

The number of chocolates eaten by X in 8 days : 2*8 = 16

Rest of the chocolates are eaten by Y in 16 days.

Chocolates left= 80-16= 64

So Y eats 64 chocolates in 16 days.

Hence efficiency of Y is : 4 chocos / day

If they work together , Total Efficiency would be (2 chocos / day+4 chocos / day)= 6 chocos / day

No of days they take together to finish 80 chocolates : (80/6)

:13 Days 8 Hours