Question

5. A can finish a piece of work in 8 days,
B in 10 days and C in 16 days. B and
C work for 4 days, then C is replaced by
A. How long will A and B take to finish
the remaining work?​

Answer 1

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Answer 2

Answer:

= 14 / 9 days or 1 and 5/9th day

Step-by-step explanation:

Given,

A does (1/8)th of the work in 1 day.

B does (1/10)th of the work in 1 day.

C does (1/16)th of the work in 1 day.

So, In 4 days that B and C work together, they do 4[(1/10)+(1/16)] or 4*26/160 or 104/160 or 13/20th of the work. What remains is 7/20th.

The remaining portion is done by A and B. A and B do (1/8)+(1/10) = 18/80 or 9/40th of the work in 1 day.

So to do 7/20th of the remaining work they will take (7/20)/(9/40) = 7*40/(9*20) = 14/9 days or 1 and 5/9th day or in less than 2 days.