Question

5. A car accelerates uniformly from 20km/h to 35km/h in 5s. Calculate (i) the
acceleration and (ii) the distance covered by the car in that time.



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Answer 1

Answer:

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Explanation:

$20 km/hr=20*5/18=5.5m/s \\ 35 km/hr=35*5/18=9.7m/s \\ time =5 seconds \\ \\ acceleration=v-u/t \\ acceleration =9.7-5.5/5 \\ acceleration=0.84m/s {}^{2} \\ \\ distance= ut+1/2at {}^{2} \\ distance=20 \times 5 + 1/2 \times 0.84 \times 25 \\distance =100+1/2 \times 21 \\ distance=100+10.5 \\ distance\: covered=110.5m$