Question

5. A car moves from A to B on semicircular path of arc ACB. Then product of distance travelled by a car and magnitude of displacement will be (Α) π/2 (B) T (C) 311 / 2 (D) 2πr2​

Answer 1

Answer:

d

Explanation:

displacement 2R

distance πR

product 2πR2

Answer 2

Answer: is D

Explanation:

because in a semicircular path the distance would be 2$\pi$r/2 and displacement would be 2r (acc. to the que we will not take it as d)  

∴ the product will be 2$\pi$r²

try solving it on your own, you will get a better explanation