Question

5. A circuit has resistance and reactance, 100 N each. Find its power factor. If the applied voltage is 200 Vrms,
calculate the average power dissipated in it in one cycl e​

Answer 1

The average power dissipated is 400 W.

Explanation:

The power factor is given as

$p=cos\phi$

Given resistance, R = reactance , X =100 OM

so, $tan\phi=\frac{X}{R} =\frac{100}{100} =1$

$\phi=\frac{\pi}{4}$

Power factor,

$cos\frac{\pi}{4}=\frac{1}{\sqrt{2} }$.

The average power dissipated in it in one cycle,

$P=\frac{(V_r_m_s)^2}{R}$

Given, $V_r_m_s=200 V$

substitute the given values, we get

$P=\frac{(200)^2}{100}$

P = 400 W.

Thus, the power dissipated is 400 W.

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