Question

5. A die is thrown six times and the number on it is noted as given below:
Number en die : 1 2 3 4 5 6
Frequency
1 1 1 1 1
What is the probability that it is a prime number?​

Answer 1

Answer:

prime number is 2 ,3,5

Step-by-step explanation:

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Answer 2

Given,

A die is thrown six times.

Frequency of occurrence of each number on the dice = 1

To find,

The probability that it is a prime number.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

The probability of occurrence of a favorable event = P (favorable event)

= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)

= (Total number of occurrence of the favorable event) / (Total number of trials)

As per the given question;

The favorable event is the occurrence of a prime number, that is 2, 3, and 5.

And, the total number of trials = 6

Now,

The probability of getting an odd number

= P(getting a prime number)

= {(frequency of occurrence of 2) + (frequency of occurrence of 3) + (frequency of occurrence of 5)} / (total number of trials)

= { 1 + 1 + 1 } / 6

= 3/6 = 1/2

=> P(getting an odd number) = 0.5

Hence, the probability of getting a prime number is equal to 0.5.