Question

5. A Fraunhofer diffraction pattern due to a single-slit of
width 0.2 mm is being obtained on a screen placed at
a distance of 2 metre from the slit. The first minima
lie at 5 mm on either side of the central maximum on
the screen. Find the wavelength of light. Ans. 5000 Å.
Diffraction of Light​

Answer 1

Answer:

10^-2m

Explanation:

the distance between the first 2 minimum of either side of the central maximum is equal to 2 lambda D/ d

where,

it is given that,

d=0.2mm

D= 2 m

lambda=5000A

is,

= (2*5*10^3*10^-10*2)/(2*10^-1*10^-3)

=10*(10^-7/10^-4)

=10^-2 m

which is the required answer.

I hope this helps.

please mark

Answer 2

Answer:

What this question

Explanation:

5. A Fraunhofer diffraction pattern due to a single-slit of

width 0.2 mm is being obtained on a screen placed at

a distance of 2 metre from the slit. The first minima

lie at 5 mm on either side of the central maximum on

the screen. Find the wavelength of light. Ans. 5000 Å.

Diffraction of Light