5. A matrix consists of 30 elements. What are the possible orders it can have?
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Concept :- when m is the number of rows , n is the number of columns then,
number of rows × number of columns = number of elements present in matrix.
Here a matrix has 30 elements so, the possible orders it can have:
1 × 30 = 30
2 × 15 = 30
3 × 10 = 30
5 × 6 = 30
6 × 5 = 30
10 × 3 = 30
15 × 2 = 30
30 × 1 = 30
Hence, there are 1 × 30, 2 × 15 , 3 × 10 , 5 × 6 , 6 × 5 , 10 × 3 , 15 × 2 and 30 × 1
number of rows × number of columns = number of elements present in matrix.
Here a matrix has 30 elements so, the possible orders it can have:
1 × 30 = 30
2 × 15 = 30
3 × 10 = 30
5 × 6 = 30
6 × 5 = 30
10 × 3 = 30
15 × 2 = 30
30 × 1 = 30
Hence, there are 1 × 30, 2 × 15 , 3 × 10 , 5 × 6 , 6 × 5 , 10 × 3 , 15 × 2 and 30 × 1
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Solution :
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If a matrix is of order m × n ,
here m is number of rows , n is number columns
So , the elements of the matrix is m × n
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Here ,
It is given that , a matrix consists of 30 elements .
All possible orders of a matrix is of the form ( m , n )
given below ,
( 1,30 ) , ( 2 , 15 ),( 3,10),( 5,6)
( 30,1) ,( 15 , 2 ) , ( 10,3) ,( 6,5 )
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