Question

5. A missile is launched from the ground mak-
ing 45° with the horizontal to hit a tar-
get at a horizontal distance of 300 km. If it is
required to hit a target at a horizontal distance of
675 km launched at same angle with horizontal, find
the percentage change in its velocity of projection.​

Answer 1

Refer to attachment:

.......

Answer 2

Answer:

49.9%

Explanation:

$R=u^{2}$ sin 2θ/2g          (R=300)

$R'=u'^{2} sin2$θ/2g           (R'=675)

% change in velocity= $(u'-u)*100/u$