Question

5.
A object is tied to the string of length and is revolved
in a vertical circle at minimum velocity when the object
reaches the upper most point the strings breaks and it
describes a parabolic path as shown in figure under
gravitational force. The horizontal range AC in the plane
of Awould be​

Answer 1

Answer: 2L

Explanation:

Answer 2

ANSWER:

    If the height is taken as h = 2L, then it can be meant that the body is thrown from a height of 2L.  

The vertical motion of the body is $u=\sqrt{g l}$

The above statement shows that the Range is R = u x t

Therefore, the range, R can be calculated as R = u x t

R =  

Now the value of time, $\mathrm{t}=\sqrt{\frac{2 h}{g}}$

Therefore, the range “R” = $u \sqrt{\frac{2 h}{g}}=\frac{\sqrt{g L .4 L}}{\sqrt{g}}=2 L$

The value of u in the above equation is taken as $u=\sqrt{g l}$ and the h = 2L.

Therefore, the range, R = 2L.