Question

5. A person travelling at a speed of 4
veiling at a speed of 40km/hr .apply the brakes giving deceleration of 6m/sec2 to his
Scooter .how far will it travel before stopping!
6.
Anarticle​

Answer 1

Answer:

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Explanation:Solution :

Initial velocity=u=43.2km/hr =43.2 x 5/18 =12 m/s

final velocity =V=0m/s [ As brakes are applied]

Acceleration=a= -6.0m/s2

Distance =s=?

Formula to be used : v²-u²=2as

s= v²-u²/2a

s=0²-12²/2x-6

S=12m

Hence distance travelled before stopping is 12m

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