Question

The mass of red planet is 0.1 times of Earth and radius is half that of earth. Compare accleration due to gravity on the planet surface to that on the earth surface

Answer 1

Hello dear,

◆ Answer-
g' = 0.4g

◆ Explanation-
# Given-
M' = 0.1M
R' = R/2

# Solution-
Acceleration due to gravity at earth's surface is calculated by-
g = GM / R^2

Acceleration due to gravity at surface of red planet is-
g' = GM' / R'^2
g' = G(0.1M) / (R/2)^2
g' = 0.4GM/R^2
g' = 0.4g

Therefore, g' = 0.4g

Hope this helps you...

Answer 2

Answer:  0.4g

Explanation: Hello dear,

◆ Answer-

g' = 0.4g

◆ Explanation-

# Given-

M' = 0.1M

R' = R/2

# Solution-

Acceleration due to gravity at earth's surface is calculated by-

g = GM / R^2

Acceleration due to gravity at surface of red planet is-

g' = GM' / R'^2

g' = G(0.1M) / (R/2)^2

g' = 0.4GM/R^2

g' = 0.4g

Therefore, g' = 0.4g

Hope this helps you...