5)A room is 8m long 6m wide. It's floor is to be covered with rectangular tiles of size 25 cm by 20 cm. How many tiles will be required? Find the cost of these tiles at Rs 25 per tile.
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Answer:
Answer
Area of room → Length X Breadth
Area of room → 1150 ×630 → 724500 sq. cm
Area of 1 tile → 23×9 → 207 sq. cm
Number of tiles required →
Area of tile
Area of room
Number of tiles required →
207
724500
→ 3500
Cost of tiling → (Number of tiles) × (Cost of 1 tile) → 3500×4.25 → 14875
l
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Answer:
length of the room =8m width of the room =6m
Area of the room LxB
8x6 =48m
m to cm
48x100 =4800cm
convert.
length of the tile =25cm width of the tile =20cm
Area of the tile = 25x20 =500cm
No. of tiles needed to to tile the
room = 4800/500-9.6 tiles. = 9 tiles and 6th of 1 tile
Rs of tiles = 9.6×25 = 240 RS
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