Question

5. A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motion is 10ms
in the downward direction, what
will be the height attained by the
stone and how much time will it
take to reach there?​

Answer 1

Answer:

Hope it will help you dude......

Answer 2

Answer:

Explanation:

Here, u=5 m/s                                              

          v=0 m/s

   and, a = g = - 10 m/s^2

now, by using 3rd eq^n of motion,

v^2 - u^2 = 2as

0 - 25 = 2 x (-10s)

- 25 = - 20s

s = -25/ - 20

s = 1.25 m

Now, by using 1st eq^n of motion

v = u + at

0 = 5 + (-10)t

- 5 / -10 = t

t = 0.5 s

therefore, required height is 1.25 m

         and, required time is 0.5 s