Question

5. A stone is thrown in a vertically
upward direction with a velocity
of 5 ms. If the acceleration of the
stone during its motion is 10 ms?
in the downward direction what
will be the height attained by the
stone and how much time will it
take to reach there?​

Answer 1

Answer:

Initial velocity =5m/s

acceleration =10m/s

final velocity =0

$v { }^{2} = u {}^{2} + 2as$

therefore, s= 5/4m

v=u+at

therefore, t=0.5 sec

Answer 2

Answer:

0.5 seconds

Step-by-step explanation:

v=u+at

v= 0

u= 5

t= ?

a= -10(as it is gravitational pull towards the earth)

So, 0= 5+(-10)t

-5= -10t

-5/-10= t

5/10= t

t= 0.5