Question

5.
A tree is broken at a height of 5 m from the ground
and its top touches the ground at a distance of
12 m from the base of the tree. Find the original
height of the tree.​

Answer 1

Answer:

This can be answered using the Pythagoras Theorem

Step-by-step explanation:

Let the fallen tree make a right angled triangle

So the height of the triangle= 5m

base= 12 m

Hypotenuse=

a2+b2=c2

5^2 + 12^2= c2

25 + 144= c2

c=$\sqrt\\169$= 13 m

Now the original height of the tree will be the height from which it fell + the hypotenuse

Original Height of the tree= 5 m + 13 m

= 18 m

Answer 2

Answer:

Original height = 18 m

Step-by-step explanation:

A tree is broken at a height of 5 m from the ground.

∴ After it was broken, current height is 5 m

And previous top touches the ground at a distance of 12 m from the base of the tree.  

∴ the broken part is like the hypotenuse of a right triangle, whose height is 5 m and base is 12 m.

∴ $(Broken part)^2 = 5^2 + 12^ = 25 + 144 = 169 = 13^2$

∴ Broken part = 13 m.

∴ Original height = (5 + 13) m = 18 m