5. a. Weight of 3 boxes of chocolate are(3p + 74 + 2) grams, (4p + 6 + 5) and (p +7q+9).
Find their total weight.
b. if the perimeter of triangle is (7x – 3y + 6)metre the lengths of two sides of the
triangle are (2x + y - 1)metre and (x – 2y + 10). Find the length of third side in terms
of x and y.
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Answer:
a. weight of the three boxes= 3p+74+2+4p+6+5+p+7q+9= 8p+7q+96
b. length of the third side= (7x-3y+6)-{(2x+y-1)+(x-2y+10)}
=(7x-3y+6)-(3x-y+9)
=4x-2y-3
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