Question

5. A wire when bent in the form of an equilateral triangle encloses an area
of 121 root 3 cm?. The same wire is bent to form a circle. Find the area
enclosed by the circle.​

Answer 1

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Area of an equilateral triangle = $\dfrac{√3a²}{4}$

Here , a = side of the triangle

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$\dfrac{√3a²}{4}=121√3$

a² = 121 ×4

a² = 484

a = √484

a = 22cm

$\small\green{ \underline{\underline{\sf{Length\:of\:the\:wire:}}}}$

a + a + a

=66cm

Now this wire is bent into a circle .

$\boxed{\red{\bf{Circumference \:of\:the\: circle=length\:of\: the\:wire}}}$

2πr = 66

$2×\dfrac{22}{7}×r=66$

$\dfrac{66×7}{2×22}=21$