Question

5. Ages of the father and his son are in the ratio 10:3. Eight years after their ages will be in
the ratio 12:5, find their present ages.​

Answer 1

Answer:

✡ Given ✡

$\leadsto$ Age of the father and his son are in the ratio of 10:3

$\leadsto$ Eight years after their ages will be in the ratio of 12:5

✡ To Find ✡

$\leadsto$ What is their present ages.

✡ Solution ✡

➡ Age of the father and his son are in the ratio of 10:3,

✏ Let the father's age be 10x

✏ Let the son's age be 3x

➡ After eight years of their age will be in the ratio of 12:5,

$\implies$ $\dfrac{(10x+8)}{(3x+8)}$ = $\dfrac{12}{5}$

$\implies$ 5(10x+8) = 12(3x+8)

$\implies$ 50x + 40 = 36x + 96

$\implies$ 50x - 36x = 96 - 40

$\implies$ 14x = 56

$\implies$ x = $\dfrac{56}{14}$

$\implies$ x = 4

▶ Hence,

$\mapsto$ Father's age = 10(4) = 40 yrs.

$\mapsto$ Son's age = 3(4) = 12 yrs.

Step-by-step explanation:

HOPE IT HELP YOU

Answer 2

Answer:

$\huge{ \bold{ \boxed{ \underline{ \mathfrak{ \star \green{answer}{} {}{} }{} }{} }{} }{} }{}$

Question :-

• Ages of the father and his son are in the ratio 10:3. Eight years after their ages will be in the ratio 12:5, find their present ages.

Answer:-

Step-by-step explanation:

$\sf{ \bold{ \red{given \: }{} }{} }{}$

• Age if father and his son are in the ratio 10:3
• After 8 years their ages are in the ratio 12:5

$\sf{ \bold{ \orange{to \: find \: out \: }{} }{} }{}$

• Father and his sons present ages

$\sf{ \bold{ \underline{ \green{detailed \: solution}{} }{} }{} }{}$

• Let the father's age be '10x'

• Let the son's present age be '3x'

After 8 years the ratio if ages = 12:5

• $= > \frac{(10x + 8)}{(3x + 8)} = =\: \frac{12}{5} \\ = > 5(10x + 8) = 12(3x + 8) \\ 50x + 40 = 36x + 96 \\ = > 50x - 36x = 96 - 40 \\ = > 14x = 56 \\ = x = \frac{56}{14} = 4$
• So, x = 4,

• Thus, The present age of father = 10*4 = 40
• And sons age = 3*4 = 12
• $\sf{ \bold{ \green{fathers \: age \: = 40 \: and \: sons \: = 12}{} }{} }{}$

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