5. An elevator is 25 m below the ground level and it ascends at the rate of 5 m/min. Find the time taken by it to reach 50 m above the ground.
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Answer:
Let s – total distance.
Then,s=25+50=75
Let v – speed of elevator, so v = 5 m/min
.Let t– time to cover total distance.
t=sv=755=
15
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