Question

Without actually calculating cubes,find the value of (15)³+(-9)³+(-6)³

Answer 1

Answer:

(i) (-12)³ + (7)³+ (5)³

 Let x = -12, y = 7 & z = 5

x + y + z = -12 + 7 + 5 = 0

Here, x + y + z = 0

We know that if,

x + y + z = 0, then x³ + y³ + z³ = 3xyz

(-12)³ + (7)³ + (5)³ = 3(-12)(7)(5) = -1260

(-12)³+ (7)³+ (5)³ = - 1260

(ii) (28)³ + (–15)³ + (-13)³

 Let x = 28, y = -15 and z = -13

x + y + z  = 28– 15 – 13 = 0

Here, x + y + z = 0

We know that if, x + y + z = 0,

 then x³ + y³ + z³ = 3xyz

(28)³+ (–15)³ + (-13)³ = 3(28)(-15)(-13) = 16380

(28)³+ (–15)³ + (-13)³ = 16380

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Answer 2

Answer :

(15)³ + (-9)³ + (-6)³

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Take cube as common :

[ 15 + (-9) + (-6)]³

=> (15 - 9 - 6)³

=> (15 - 15)³

=> 0³

= 0

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