Question

5.
An experiment has four possible outcomes A, B, C and D that are mutually exclusive. Expla
why the following assignment of probabilities are not permissible :
(1) P(A)=0.12, P(B) = 0.63, P(C) = 0.45, P(D)=-0.20.
45
27
46
(ii) P(A) = P(B) =
P(D)=
120
120
120
9
=
120P(C)​

Answer 1

Answer:

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Step-by-step explanation:

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