Question

5. An object at rest on a frictionless plane is pushed with a steady force of 10N for 8
seconds. Find its momentum at the end of 8th second.
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Answer 1

Answer:

p=80kgm/s

Explanation:

We need to find p=mv at t=8

Let mass be 'm'

Then,

$a=F/m\\a=10/m$

Now,

$v=u+at\\v.m/s=0+\frac{10N}{m.kg}8s\\v=\frac{80}{m}\\mv=80 kgms^{-1}$

Answer 2

Given :

➳ Applied force = 10N

➳ Initial momentum = zero (i.e., rest)

To Find :

⟶ Final momentum of object after the given interval of time.

SoluTion :

➢ As per Newton's second law of motion, Force is defined as the rate of change of linear momentum.

Mathematically, F = dP/dt

• F denotes Force
• dP denotes change in momentum
• dt denotes change in time

➢ Momentum is defined as the product of masd and velocity.

⇒ F = (Pf - Pi) / dt

⇒ 10 = (Pf - 0) / 8

⇒ Pf = 10 × 8

⇒ Pf = 80 Ns