Question

5. Anaonaplane Flying horizontally
at a height o.49km with a vections
at 98 mlo realsed a bomb
on Reitching the ground velocity
of the bomb is
2​

Answer 1

Answer:

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Explanation:

Hey mate,

● Answer-

v = 98√2 m/s

● Explanation-

Velocity of the bomb has two components.

Horizontal component is same as that of aeroplane.

vx = 98 m/s

Vertical component is given by-

vy^2 = u^2 + 2gh

vy^2 = 0^2 + 2×9.8×490

vy = 98 m/s

Resultant velocity

v = √(vx^2 + vy^2)

v = √(98^2 + 98^2)

v = 98√2 m/s.

Velocity of the bomb is 98√2 m/s.

Hope that is all...