Question

√5 and -√5 are two zeroes of p(x) =x^3 + x^2 - 5x - 5 then find its third zero​

Answer 1

Answer:

Let third zero be -1

Step-by-step explanation:

$x {}^{3} + x {}^{2} - 5x - 5 = 0$

$x {}^{2} (x + 1) - 5(x + 1)$

$(x {}^{2} - 5)(x + 1)$

$x = - \sqrt{5}$

$x = \sqrt{5}$

$x = - 1$

Answer 2

Answer:

28

for ur Frist question