Question

5. Calculate mass of Sulphur molecules which are exactly equal in number of molecules of phosphorus present in 186 g of phosphorus.​

Answer 1

198 g of Sulfur

Explanation:

Given: Molecular weight of Phosphorus = 31 g

1) Number of molecules in 186 g of phosphorus:

30 g of phosphorus contain 6.022 × 10²³ molecules of phosphorus

186 g of phosphorus = 6.022 × 10²³ × 186/30

                                   = 37.33 × 10²³ number of molecules of Phosphorus

2)  Mass of Sulphur:

32 g of sulfur contain 6.022 × 10²³ molecules of Sulfur

x g of sulfur contain  37.33 × 10²³ number of molecules of sulfur

x = 37.33 × 10²³ × 32/  6.022 × 10²³

  = 198 g of Sulfur

 

Answer 2

Answer:

192g of Sulphur

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