Question

5 chair and 3 tabel cost 750 and 3 chair and 3 tables cost 540. Find cost of 1 chair and one table

Answer 1

Step-by-step explanation:

let number of chairs be=x and that of tables be= y

Ist case:

5x+3y=750.........1

2nd case:

3x+3y=540

=x+y=180...........2

eliminating 2from 1 ,we get

5x+3y=750

X+ y= 180

- - -

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4x+2y=570

Answer 2

Step-by-step explanation:

Given:

Cost of 5 chair and 3 table is 750

Cost of 3 chair and 3 table is 540

To Find:

Cost of 1 chair and 1 table

Solution:

Let one chair cost be x and one table cost be y

Therefore, cost of 5 chair = 5x

cost of 3 chair = 3x

cost of 3 table = 3y

According to the Problem,

5x + 3y = 750 --------------(i)

3x + 3y = 540 --------------(ii)

Now subtract (i) from (ii)

5x + 3y - 3x - 3y = 750 - 540

or, 2x = 210

or, x = 105

Putting value of x in (ii)

3*105 + 3y = 540

or, 315 + 3y = 540

or, 3y = 225

or, y = 75

Therefore, cost of one chair = 105

cost of one table = 75

Therefore, Cost of one chair and one table =(105+75) = 180

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