Question

5. Check whethen 6h an end with the digit o for any
natural number n.
​

Answer 1

No,

6^n never ends with digit 0 where n is a natural number because 6^n always ends with digit 6 but not digit 0

PROOF:-

6^1 = 6

6^2 = 36

6^3 = 216

They all end with digit 6

Answer 2

$\huge\boxed{\texttt{\fcolorbox{purple}{blue}{Heya !!!}}}$

LET US ASSUME THAT

$6 {}^{n}$

ENDS WITH ZERO.

SO,

$(3 \times 2) {}^{n} = 5 \times 2$

AS IN THE PRIME FACTORISATION OF 6 THERE IS NO 5.

OUR PREASSUMPTION IS WRONG.

HENCE 6 ^n DOES NOT WITH 0.

HOPE IT HELPS ⭕⭕⭕

MARK BRAINLIEST

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