Question

5 cm tall object is placed at the distance of 30 cm from a convex mirror of focal length 15cm find the position size and nature of the image formed
​

Answer 1

Answer:

1/f=1/v+1/u

1/15=1/v+(-1/30)

1/15=1/v-1/30

1/v=1/15+1/30

1/v= 2+1/30

1/v=3/30

1/v=1/10

v=10 cm(position of image)

-v/u=I/O

-10/30 = I/5

-50=I×-30

I=-50/-30

I = 50/30

I = 5/3

I= 1.66cm (approx)

Answer 2

Answer:

Explanation:at first find find the value of V by using mirror formula.... Take u-negative, and f- positive. If M will be positive then the nature of image will be virtual and erect.....