Question

5. Construct ∆DEF, in which DE = 5 cm, DF = 3 cm and m ∆EDF = 90°​

Answer 1

. Draw a line segment DF = 3cm

2. Draw a semi circle of any radius. Cut an arc on the semi circle using the same radius.

3. Again , using the same radius cut an arc from the previous arc.

4. Now from each arc on the semi circle, make two arcs cutting each other.

5. Now, from point D, using radius of 5 cm, straight from point D and name it point E.

6. Join DE and EF.

7. Hence, EDF is the required triangle.

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Answer 2

Step-by-step explanation:

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