5 cos 0 degree minus 2 sin 30 degree + root 3 cos 30 degree divided by Tan 30 degree into tan 60 degree into cos 30 degree + 3 Sin 29 degree ×+61 degree
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(5 × 1 - 2 × 1/2 + √3 × √3/2)/(1/√3 × √3 × 1/2 + 3sin29° sec61°)
= (5 - 1 + 3/2)/[1/2 + 3sin(90° - 61°) sec61°]
so, sin(90° - 61°) = cos61°
also secθ = 1/cosθ
= (4 + 3/2)/[1/2 + 3cos61° × 1/cos61°]
= [(8 + 3)/2]/[1/2 + 3]
= (11/2)/(7/2)
= 11/7
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Answer:
Step-by-step explanation:
The answer is 11/7
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