Question

find the zeros of the following Pani polynomial 5 under root 5 x square + 30 X + 8 under root 5

Answer 1

$5 \sqrt{5} \: {x}^{2} + 30x + 8 \sqrt{5} \\ \\ a = 5 \sqrt{5} \\ b = 30 \\ c = 8 \sqrt{5} \\ \\ x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{ - 30 \pm \sqrt{ {30}^{2} - 4 \times 5 \sqrt{5} \times 8 \sqrt{5} } }{2 \times 5 \sqrt{5} } \\ \\ x = \frac{ - 30 \pm \sqrt{900 - 800} }{10 \sqrt{5} } \\ \\ x = \frac{ - 30 \pm \sqrt{100}}{10 \sqrt{5} } \\ \\ x = \frac{ - 30 \pm 10}{10 \sqrt{5} } \\ \\ x = \frac{ - 30 + 10}{10 \sqrt{5} } \: \: and \: \: \frac{ - 30 - 10}{10 \sqrt{5} } \\ \\ x = \frac{ - 20}{10 \sqrt{5} } \: \: and \: \: \frac{ - 40}{10 \sqrt{5} } \\ \\ \boxed{ \red{x = \frac{ - 2}{ \sqrt{5} } \: \: and \: \: \frac{ - 4}{ \sqrt{5} } }}$

Answer 2

Answer:

2/√5   and-4/√5

Step-by-step explanation:

use quadratic formula.