A piece of thin wire in the form of an equilateral triangle of side 31.4 cm is bent into a ring with no loss of wire. Find the diameter of ring
A: 20 CM
B:10 CM
C:15 CM
D:30 CM
Answers
Answered by
2
Answer:
30 cm
Option D
Step-by-step explanation:
One side of equilateral triangle = 31.4 cm
Perimeter = 31.4 + 31.4 + 31.4 = 3 * 31.4 cm
Perimeter of circle = Pie * Diameter
= > 3.14 * Diameter = 3 * 31.4
=> Diameter = 30 cm
shahidkhan243503:
S0RRY, YOU ARE WRONG THE CORRECT ANSWER IS 15 CM
Dear 15 cm will be the radius. Diameter will be 2*15 = 30 cm
Please mark as brainliest if it helped
Answered by
0
Answer:-20cm
Step-by-step explanation:so a/c to your question
Let 1 side of triangle be x
Therefore 3x=circumference of circle so formed
= 3×31.4cm=circumference
94.2cm=circumference
Now,
Circumference=2× pie × r
94.2 =2×22/7×r
94.2×7/44=r
14.98=r
Therefore d=2r
d=2×14.98
D=19.96cm
=20cm(aprox.)
2×14.98 = 29.96 not 19.96
you could better use pie = 3.14 instead of 22/7
But using 22/7 is better
And if accessory to use3.14 that it must be given in the question.
It's question of y
9th standard
31.4 / 3.14 = 10 thats why i said to use pie = 3.14 . Its always better to choose value of pie 22/7 or 3.14 depending on other data
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