5 cos A- 12 sin A=0 find value of sin A + cos A / 2cos A - sin A
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Answered by
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5cosA - 12sinA =0
==> 5cosA = 12sinA
==> cosA = 12sinA/5
Substituting this value of cosA in sinA+cosA/2cosA-sinA
= (sinA + 12sinA/5) / {2*(12sinA/5) - sinA}
= (5sinA + 12sinA)/5 / (24sinA - 5sinA)/5
= 17sinA / 19sinA
= 17/19
The final answer is 17/19. Hope this helps!
==> 5cosA = 12sinA
==> cosA = 12sinA/5
Substituting this value of cosA in sinA+cosA/2cosA-sinA
= (sinA + 12sinA/5) / {2*(12sinA/5) - sinA}
= (5sinA + 12sinA)/5 / (24sinA - 5sinA)/5
= 17sinA / 19sinA
= 17/19
The final answer is 17/19. Hope this helps!
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