Math, asked by Rehannazeer, 1 month ago

5 Draw a triangle ABC with AB = 6 cm, BC = 7 cm and CA = 8 cm. Using ruler and compass
alone, draw (i) the bisector AD of ZA and (i) perpendicular AL from A on BC.
Measure LAD.​

Answers

Answered by Yenay
8

\huge\purple{\mid{\fbox{\tt Hi\:Mate}\mid}}

\Large\bold{\underline{\pink{Construction:}}}

\small\bold\orange{Step:1}

Draw a line segment BC of length 7 cm.

\small\bold\orange{Step:2}

With center B, draw an arc of radius 6 cm.

\small\bold\orange{Step:3}

With center C, draw an arc of radius 8 cm intersecting the previously drawn arc at A.

\small\bold\orange{Step:4}

Join AC and BC to get the required triangle.

\small\bold\orange{Step:5}

Angle bisector from A, cut arcs of equal radius intersecting AB and AC at E and F, respectively.

\small\bold\orange{Step:6}

From E and F, cut arcs of equal radius intersecting at point H.

\small\bold\orange{Step:7}

Join AH and extend to produce the angle bisector of angle A, meeting line BC at D.

\small\bold\orange{Step:8}

Perpendicular from Point A to line BC steps. From A, cut arcs of equal radius intersecting BC at P and Q, respectively (Extend BC to draw these arcs).

\small\bold\orange{Step:9}

From P and Q, cut arcs of equal radius intersecting at M.

\small\bold\orange{Step:10}

Join AM cutting BC at L.

\small\bold\orange{Step:11}

AL is the perpendicular to the line BC.

\small\bold\orange{Step:12}

Angle LAD is 15°

\Large\color{aqua}Happy\:Learning

\Large\fbox\red{Mark\:As\:Brainliest}

Attachments:
Similar questions