Question

Question:-Find the value of x²+y²,if x+y=6,xy=8.
Pls answer this it's very urgent ​

Answer 1

Step-by-step explanation:

x^2+y^2=(x+y)^2-2xy

=6^2-2×8

=36-16

=20

Answer 2

$\sf{Answer}$

Step by step explanation:-

Given :-

x + y = 6

xy = 8

To find :-

x² +y²

We know that !!

( x + y)² = x² +y²+2xy

Lets substuite values !!

(x +y)² = x²+y²+2xy

(6)² = x²+y² +2(8)

36 = x²+y² +16

36 -16 = x²+y²

20 = x²+y²

Required answer:-

So,the value of x²+y² is 20

Know more algebraic identities:-

(a -b)²= a²+b²-2ab

(a+b)(a-b) = a²-b²

(a+b)³ = a³+b³+3ab(a+b)

(a-b)³ = a³-b³-3ab(a-b)

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