Question

5. Evaluate i-2001 + i^-2002 +i^-2003
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Answer 1

Step-by-step explanation:

i^(-2001)+i^(-2002)+i^(-2003)=1/(i^2001)+1/(i^2002)+1/(i^2003)

as we know that i^4n=1 then i^500×4=i^2000=1

so,1/(i^1)+1/(i^2)+1/(i^3)=(i^3-1+i)

as we know that i^3= -i

so i^3-1+i = -i-1+i = -1

so your answer is -1

thanks