Prove that in a convex hexagon, the sum of interior angle is equal to the twice the sum of the exterior angle.
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Answer:
In a hexagon number of sides=6
∴ Sum of interior angles of a hexagon=(2×6−4)×90°=8×90°=720°
Sum of exterior angle of a hexagon =360°
2 times the sum of exterior angles of hexagon =2×360
=720
From (1)&(2)
In a convex hexagon the sum of all interior angle is equal to twice of exterior angles.
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3
Answer:
In a hexagon number of sides=6
∴ Sum of interior angles of a hexagon=(2×6−4)×90°=8×90°=720°
Sum of exterior angle of a hexagon =360°
2 times the sum of exterior angles of hexagon =2×360
=720
From (1)&(2)
In a convex hexagon the sum of all interior angle is equal to twice of exterior angles.
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