Question

5. Factorise:
(i) 4x² +9y² + 16z² + 12xy - 24yz - 16xz​

Answer 1

Answer:

(2x+3y-4z)²

Step-by-step explanation:

we have,

4x²+9y²+16z²+12xy-24yz-16xz

=(2x)²+(3y)²+(-4z)²+2(2x)(3y)+2(3y)(-4z)+2(-4z)(2x)

=[2x+3y+(-4z]²

=(2x+3y-4z)²

If you are satisfied mark me as Brainliest

Answer 2

Answer:

4x^2 + 9y^2 + 16z^2 + 12xy - 24yz - 16xz

We use this identity here

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca

4x^2 + 9y^2 + 16z^2 + 12xy - 24yz - 16xz

= (2x)^2 + (3y)^2 + (4y)^2 + 2 × 2x × 3y + 2 × 3y × (-4y) + 2 × 2x × (-4y)

= (2x + 3y - 4y)^2

= (2x + 3y - 4y) (2x + 3y - 4y)