Question

5. Find the area of an isosceles right triangle having the length of each equal side 5 ​

Answer 1

Given:-

• Length of each equal side 5 cm.

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To find:-

• Area of an isosceles right triangle.

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Solution:-

☆Area of triangle = 1/2 bh

→ 1/2 × 5 × 5

→ 2.5 × 5

→ 12.5 cm²

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Hence,

• the area of the triangle is 12.5 cm².

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⠀⠀⠀⠀⠀Some Formulae

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→ Area of square = (side)²

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→ Area of rectangle = length × breadth

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→ Area of triangle = ½ × base × height

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→ Area of parallelogram = base × height

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→ Area of Circle = πr²

Answer 2

GiveN:

• Length of an isosceles right triangle of each equal side 5cm

To FinD:

• Area of the triangle

Formula used:

• $\bf \dfrac{1}{2} \times base \times height$

Required Solution:

• As, it's given that the length of each equal side is 5cm.
• So, Both base and height is 5cm

$\sf⇛ \: \: \: \: \: \: \: \: \: \: \: \dfrac{1}{2} \times( 5 \times 5) \\ \\ \sf \: ⇛ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{1}{2} \times 25 \: \: \: \: \: \: \: \: \: \\ \\ \sf \: ⇛ \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{25}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \: ⇛ \: \: \: \: \: { \boxed{\bf{ \bigstar{ \purple{ \pink{12.5 \: sq.cm }}}}}}$

So,

• Base of the isosceles triangle = 5cm.
• Height of the isosceles triangle = 5cm.
• Area of the isosceles triangle = 12.5 sq.cm