Question

5. Find the area of the sector which has radius 6cm and perimeter 58cm.
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Answer 1

Answer:

D=12㎝⇒r= 6cm

θ /360°  ×2πr+2r=58㎝⇒ θ / 360° ×2×  22 /7×6+2×6=58

198θ /360°×7 +9=58⇒θ

=  7×360° /198  (58−9)

=623.64°

Area= θ / 360°   ×πr  2  

= 623.64° /360° 22/7  ×6×6

=110.25㎠

Answer 2

Step-by-step explanation:

perimeter =2r+l

58= (2*6)+l

58=12+l

58-12=l

46=l

area of sector=lr /2

=(44*10) /2

=22*10

=220cm sq