Question

5. Find the area of trapezium where length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm. no spamming allowed..​

Answer 1

Given : A length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.

$\begin{gathered} \\ \end{gathered}$

To Find : Area of trapezium ?

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SolutioN :

• Let us assume that, the area of trapezium be x cm.

$\begin{gathered} \\ \end{gathered}$

${ \maltese{ \color{blue}{ \underline{ \underline{ \sf{ \: According \: to \: the \: Question :}}}}}}$

$\begin{gathered} \\ \qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~(a~+~b)~×~h}} \end{gathered}$

$\begin{gathered} \\ \qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~(15~+~25)~×~12}}\end{gathered}$

$\begin{gathered} \\ \qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~(40)~×~12}}\end{gathered}$

$\begin{gathered} \\ \qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1}{2}~×~480}}\end{gathered}$

$\begin{gathered} \\ \qquad{\sf:\implies{Area_{(Trapezium)}~=~\dfrac{1~×~480}{2}}}\end{gathered}$

$\begin{gathered} \\ \qquad{\sf:\implies{Area_{(Trapezium)}~=~\cancel\dfrac{480}{2}}}\end{gathered}$

$\begin{gathered} \\ \qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area_{(Trapezium)}~=~240cm^2 }}}}}}\end{gathered}$

$\begin{gathered} \\ \end{gathered}$

Hence,

$\qquad ∴$ The area of trapezium is = 240cm².

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Answer 2

Question :-

5. Find the area of trapezium where length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.

Answer :-

$\large \boxed{ \sf {30Cm }}$

Explanation :-

Let the side below which is the base = x

then the length of the base = 18cm+x

the area of a trapezium is found by using the formula

A = 1/2(b1+b2)xh

where

A = area = 126cm^2

b1 = 18cm

b2 = 18+x cm

h = 5.25cm

126 = 1/2(18+18+x)*5.25

126 = 1/2(94.5+94.5+5.25x)

126 = 1/2(189+5.25x)

126 = 94.5+2.625x

126–94.5 = 2.625x

31.5 = 2.625x

x = 31.5/2.625

x = 12

therefore the length of the base = 18+12= 30cm

Confirming the answer by plugging the length of the base back into the formula for finding the area of a trapezium

126 = 1/2(18+30)*5.25

126 = 1/2(48)*5.25

126 =24*5.25

126 = 126

Confirming that 30 cm was the correct answer

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Description :-

• ➥Sorry for not given latex Answer because lots of time expense.